1520B - Ordinary Numbers - CodeForces Solution


brute force math number theory *800

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Python Code:

n = int(input())
for i in range(n):
    a = int(input())
    b = a//10
    if b == 0:
        print(a)
    else:
        c = len(str(b))*9
        d = a//int(int(len(str(a)) * '1'))
 
        print(d+c)
 	  		 	  	 	 	 	      	    	

C++ Code:

#include <bits/stdc++.h>
#define ll long long
#define db double
#define str string
#define vi vector<int>
#define vll vector<ll>
#define maax(a,b,c) max(max(a,b),c)
#define diff(a,b) abs(a-b)
#define pi 2*asin(1)
#define pb push_back
#define mp make_pair
#define sfi(a) scanf("%d", &a)
#define sfl(a) scanf("%lld", &a)
#define sfc(a) scanf("%ch",&a)
#define pf printf
#define pii pair<int, int>
#define all(x) x.begin(),x.end()
#define iobost ios_base::sync_with_stdio(false), cin.tie(0), cout.tie(0)
#define el '\n'
#define sp ' '
//318424JO timus judge id
using namespace std;

int main()
{
	iobost;
	int t;
	cin>>t;
	while(t--)
	{
		int n;
		cin>>n;
		int ans=0;
		for(int power=1;power<=n;power=power*10+1)
		{
			for(int d=1;d<10;d++)
			{
				if(d*power<=n)ans++;
			}
		}
		cout<<ans<<el;
	}
    return 0;
}


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